Sophie.A

629998. Mon Oct 26, 2009 7:08 pm 


388 = ( Γ(Γ(4)) − 4! ) × 4 + 4 




Vera C

630000. Mon Oct 26, 2009 7:09 pm 


389 = ( Γ(Γ(4)) − 4! ) × 4 + 4 + Γ(√4)
389 = (4² + T(4))² + 4! + 4 Last edited by Vera C on Thu Oct 29, 2009 7:20 am; edited 2 times in total





costean

630749. Thu Oct 29, 2009 2:37 am 


390 = (4! x 4²) + 4 + √4 




samivel

630750. Thu Oct 29, 2009 2:53 am 


Vera C wrote:  389 = ( Γ(Γ(4)) − 4! ) × 4 + 4 + Γ(√4) 
I know it seems unfair for me to point out a possible error when I haven't a clue how to correct it, but isn't that one digit 4 too many? 




Vera C

630785. Thu Oct 29, 2009 7:11 am 


Yes, you're quite right. Thanks for pointing it out. I've changed it to something better.
391 = (4! x 4²) + 4 + T(4) 




ali

630960. Thu Oct 29, 2009 7:03 pm 


392 = 4! * 4^√4 + 4!! 




Sophie.A

632810. Tue Nov 03, 2009 6:23 pm 


This is all perhaps getting a bit too easy. How about trying three 3’s?





WordLover

762322. Wed Nov 24, 2010 10:20 am 


Vera C wrote:  Yes, you're quite right. Thanks for pointing it out. I've changed it to something better.
391 = (4! x 4²) + 4 + T(4)  To correct Vera: (4! x 4²) + 4 + T(4) = 398, not 391.
391 = T(T(gamma(4)))+sqrt(sqrt(sqrt(4^4!)))/.4
392 = 4*(4*4!+sqrt(4)) 




Vera C

763943. Tue Nov 30, 2010 4:56 pm 


WordLover wrote:  Vera C wrote:  Yes, you're quite right. Thanks for pointing it out. I've changed it to something better.
391 = (4! x 4²) + 4 + T(4)  To correct Vera: (4! x 4²) + 4 + T(4) = 398, not 391. 
Oops. How about
391 = (4! x 4²) + Г(4) + Г(√4) 




bobwilson

764270. Wed Dec 01, 2010 11:20 pm 


That doesn't work  that includes 4 to the power 2 




aTao

764275. Thu Dec 02, 2010 1:46 am 


Quote:  Use the digit 4, up to four times to make 1,2,3 … etc
Using: + , ÷ , × ,  , √ , ( ) , ( )^2 and ! (as many times as necessary) 
4 to the power 2 = (4)^2 




WordLover

764626. Fri Dec 03, 2010 9:53 am 


Quote:  Use the digit 4, up to four times to make 1,2,3 … etc
Using: + , ÷ , × ,  , √ , ( ) , ( )^2 and ! (as many times as necessary) 
and T(), phi() and gamma(). I think that that makes the problem too easy, though it's still rather a challenge if you limit yourself to 3 4s.
392 (see above)
393 = (gamma(4)+4^4)/sqrt(:4)
where by :4 I mean .4 recurring. 




Vera C

765371. Mon Dec 06, 2010 2:36 pm 


394 = (4! x 4^(√4)) + T(4) 




WordLover

765472. Tue Dec 07, 2010 3:08 am 


395 = T(T(gamma(4))+gamma(4)) + T(gamma(4))  4 




joefoxon1

806619. Sat Apr 16, 2011 4:59 pm 


396= (4!)(4^2)+(4^2)4 



